fix: 修复列表筛选空参与树数据展示
将后端 status/audit_status 筛选从 has() 改为 filled(),避免空字符串导致列表被误筛空;修复预定 status=0 筛选失效;前端兼容财务分类树形返回与菜单/字典数组返回,解决新增成功但列表空。
This commit is contained in:
@@ -15,7 +15,7 @@ class ReservationController extends Controller
|
||||
$query = Reservation::query()->with(['customer', 'room.roomType']);
|
||||
$query->when($request->customer_id, fn($q, $v) => $q->where('customer_id', $v));
|
||||
$query->when($request->room_id, fn($q, $v) => $q->where('room_id', $v));
|
||||
$query->when($request->status, fn($q, $v) => $q->where('status', $v));
|
||||
$query->when($request->filled('status'), fn($q, $v) => $q->where('status', $v));
|
||||
$query->when($request->check_in_date, fn($q, $v) => $q->whereDate('check_in_date', $v));
|
||||
|
||||
return $this->paginate($query->latest()->paginate($request->input('per_page', 15)));
|
||||
|
||||
@@ -13,7 +13,7 @@ class RoomTypeController extends Controller
|
||||
{
|
||||
$query = RoomType::query()->withCount('rooms');
|
||||
$query->when($request->name, fn($q, $v) => $q->where('name', 'like', "%{$v}%"));
|
||||
$query->when($request->has('status'), fn($q) => $q->where('status', $request->status));
|
||||
$query->when($request->filled('status'), fn($q) => $q->where('status', $request->status));
|
||||
|
||||
return $this->paginate($query->orderBy('sort')->paginate($request->input('per_page', 15)));
|
||||
}
|
||||
|
||||
Reference in New Issue
Block a user